![]() ![]() Should something happen and the heater draw more than 30amps, you might then have a problem but the heater itself should have its own protections against over pulling. In this case if your 30amp heater were to pull the max, then you would be running at 100% of the rating. If the heater is rated for 30 amps and you put a 30 amp breaker on there, then you are at a highly slighter risk as it is generally recommended to not exceed 80% of the breakers rating. Get your wiring accessories out One 50 amp outlet (or NEMA 14-50R), a wire (6 or six-gauge is highly recommended), and a weather-resistant box. In this case if the wiring is rated for 50amps, I would put the 50amp system back on there. White (or neutral wire) goes directly below it, on the silver screw (or terminal). Think of it like this, the device will only draw as much amperage as it needs so as long as you stay below the max for the circuit then you are ok. Compatible with Siemens PL and ES series load centers. Siemens type QP circuit breakers provide easy plug-in connections in Siemens enclosures and the time saving insta-wire feature. This is what allows you to plug in, for example, five different devices into one circuit as long as the combination of those devices do not exceed the total amperage of the circuit. 2-pole, 50 Amp, 240-Volt type QP circuit breaker. ![]() Only GFCI requirement is for 120v outlets where you can plug in a hand operated device. Some industrial electric stoves need a 60 amp breaker, while older ones can get away with 30 amp breakers. Based on everyones advice, I checked with our local electrical inspector who confirmed the prevailing view that no GFCI is required for either the 240v outlets or dedicated unit heater. The majority of devices that you plug in will be less amperage than the circuit provides and this is kind of the point. Most 240-volt electric stoves require a 50 amp double-pole circuit breaker with a 8 gauge copper wire or 6 gauge aluminum wire. Putting a higher amp device on a lower amp circuit = might be a problem Putting a lower amp device on a higher amp circuit = Not a problem. ![]()
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